已知,如图,AE=CF,角DAF=角BCE,AD=CB
来源:学生作业帮 编辑:灵鹊做题网作业帮 分类:数学作业 时间:2024/04/29 04:59:35
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解题思路: 三角形全等的判定方法
解题过程:
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最终答案:略
解题过程:
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最终答案:略
已知,如图,AE=CF,角DAF=角BCE,AD=CB
已知:如图,AE=CF,∠DAF=∠BCE,AD=CB.
已知:如图所示,在四边形ABCD中,AD=CB,∠DAF=∠BCE,AE=CF且AB∥CD.求证:△ADF≌△CBE
已知,如图,AB=AD,AE=AF,CB=CD,CE=CF.求证:∠DAF=∠BAE
已知,如图,AB=AD,CB=CD,CE=CF.求证:∠DAF=∠BAE
如图,已知AD‖BC,AD=CB,AE=CF.求证:DF=BE
如图,已知AD=CB,AE=CF,DE=BF,求证AB=CD.
如图,已知AD=CB,AE=CF,DE=BF,求证:DE∥BF
如图,已知AD=CB,AE=CF,DE=BF,求证:AB∥CD
如图,已知AD=CB,AE=CF,DE=BF,求证:DE∥BF.
已知,如图:点A E F C在一条直线上,AE=CF,角B=角D,AD平行BC,求证:AD=CB
如图,已知AE=CF.∠D=∠B,AD=CB,求证:AD∥BC