(sin2x)除以(sinx+cosx-1)(sinx-cosx+1)等于cotx/2 证明:
来源:学生作业帮 编辑:灵鹊做题网作业帮 分类:数学作业 时间:2024/05/03 01:20:38
(sin2x)除以(sinx+cosx-1)(sinx-cosx+1)等于cotx/2 证明:
等式左边=2sinxcosx/[sinx+(cosx-1)][sinx-(cosx-1)]=2sinxcosx/[sin^2x-(cosx-1)^2]=2sinxcosx/(sin^2x-cos^2x+2cosx-1)=2sinxcosx/(2cosx-2cos^2x)=sinx/(1-cosx)=2sin(x/2)cos(x/2)/[1-2cos^2(x/2)+1]=sin(x/2)cos(x/2)/[1-cos^2(x/2)]=sin(x/2)cos(x/2)/sin^2(x/2)=cot(x/2)
(sin2x)除以(sinx+cosx-1)(sinx-cosx+1)等于cotx/2 证明:
求证:(sin2x)除以(sinx+cosx-1)(sinx-cosx+1)等于cotx/2
证明(1+cosx)/sinx=cotx/2
lg(sinx+cosx)+lg(sinx+cosx)-(lg1+sin2x)为什么等于lg(sinx+cosx)/1+
证明(cosx+sinX)^2=1+sin2X
sin2X/(1+cosX+sinX)化简
∫[(sinx-cosx)/1+sin2x]dx
若(1+sinx)除以cosx等于-0.5,则cosx除以(sinx-1)等于多少
化简:(sin2x/sinx-cosx)-(sinx+cosx/tan2x-1)那个2是平方的意思
证明(1+sinx + cosx)/(1+sinx - cosx)=(1+cosx+cotx+cscx)/(1+sinx
化简((sinx+cosx-1)(sinx-cosx+1)-2cosx)/sin2x
证明1+sin2x/sinx+cosx=sinx+cosx(详细答案)