怎样化简函数 cosπ/4cosπ/3-sinπ/4sinπ/3
怎样化简函数 cosπ/4cosπ/3-sinπ/4sinπ/3
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/2) 化简为sin的形式
(sinθcosπ/3)-(cosθsinπ/3)怎么化简得sin(θ-π/3)
cos sin π √
已知 sin(θ+kπ)=-2cos (θ+kπ) 求 ⑴4sinθ-2cosθ/5cosθ+3sinθ; ⑵(1/4)
已知α∈(0,π/2),且2sinα-sinαcosα-3cosα=0.求[sin(α+π/4)]/[sin2α+cos
已知3π/4最好把tan化成sin/cos,cot化成cos/sin算,因为我是这样的,然后算得sin@cos@=-3/
已知tan(π-α)=2,求sinα-2sinαcosα-cosα/4cosα-3sinα的值
已知(sinα-cosα)/(sinα+cosα)=1/3,则cos^4(π/3+α)-cos^4(π/6-α)的值为
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)
已知函数f(x0=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)
已知函数fx=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)