(sinθcosπ/3)-(cosθsinπ/3)怎么化简得sin(θ-π/3)
(sinθcosπ/3)-(cosθsinπ/3)怎么化简得sin(θ-π/3)
若(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)等于?
sin(π-θ)+cos(2π-θ)/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=_____
1.已知2sin(3π+θ)=cos(π+θ),求2sin
三角函数化简[2cos^3θ+sin^2(π-θ)+sin(π/2+θ)-3]/[2+2cos^2(π+θ)+cos(-
(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)=
参数方程化为普通方程 x=(sinθ+cosθ)/(2sinθ+3cosθ) y=sinθ/(2sinθ+3cosθ)
sinθ=3×cosθ (sinθ)²=()×(cosθ)²
怎样化简函数 cosπ/4cosπ/3-sinπ/4sinπ/3
(cosπ/8+sinπ/8)(cos^3π/8-sin^3π/8)
已知 sin(θ+kπ)=-2cos (θ+kπ) 求 ⑴4sinθ-2cosθ/5cosθ+3sinθ; ⑵(1/4)
已知(3sinα+cosα)/(3cosα-sinα)=2,则2-3sin(α-3π)sin(1.5π-α)-[cos(