x+y/2=z+x/3+y=z/4,...x+y+z=27.解方程组.

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x+y/2=z+x/3+y=z/4,...x+y+z=27.解方程组.
X+Y/2=Z+X/3=Y+Z/4,X+Y+Z=27.解方程

设(x+y)/2=(x+z)/3=(y+z)/4=k
则x+y=2k x+z=3k y+z=4k
代入x+y+z=27
2k+3k+4k=27 k=3
所以 x+y= 6 (1)
x+z=9 (2)
y+z=12 (3)
(1)+(2)+(3) 2(x+y+z)=27 x+y+z=27/2 (4)
(4)-(1) z=15/2
(4)-(2) y=9/2
(4)-(3) x=3/2
即为所求

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