设函数f(x)=-1/3x^3+2ax^2+1/3a(0
设函数f(x)=-1/3x^3+2ax^2+1/3a(0
设函数f(x)=x^3+ax^2-9x-1(a
设函数f(x)= -1/3x^3+2ax^2-3a^2x+a/3(0
设函数f(x)=x^3+ax^2-a^2x+1,g(x)=ax^2-2x+1,其中实数a不等0
设函数f(x)=ax^2+bx+c((a≠0),满足f(x+1)=f(-x-3),且f(-2)>f(2),解不等式f(-
设函数f(x)=-1/3x~3+2ax~2-3a~2x+1(0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+1(0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-2a^2x+b,0
设函数f(x)=1/3x^3-ax^2-3a^2-5/3(a>0)
设函数f(x)=3ax²-2(a+c)x+c(a>c>0).函数f(x)在区间(0,1)内是否有零点?为什么?
设函数f(x)=x^3+ax^2-a^2x+1,g(x)=ax^2-2x+1,其中实数a不等0,若a>0,求函数f(x)