灵鹊做题网matlab解一元二次方程
来源：学生作业帮 编辑：灵鹊做题网作业帮 分类：数学作业 时间：2024/05/03 11:44:45
matlab解一元二次方程
求解方程（a-2a*s*t）^2+[b+(sinα+4f*s)t-f]^2=R^2
其他系数均为已知,求t,难道我只能开平方整理成ax^2+bx+c=0的形式吗?
求解方程（a-2a*s*t）^2+[b+(sinα+4f*s)t-f]^2=R^2
其他系数均为已知,求t,难道我只能开平方整理成ax^2+bx+c=0的形式吗?
syms a s t a1 f R t
>> t=solve('(a-2*a*s*t)^2+(b+(sin(a1)+4*f*s)*t-f)^2=R^2',t)
t =
((4*R^2*a^2*s^2 + 16*R^2*f^2*s^2 + 8*R^2*f*s*sin(a1) + R^2*sin(a1)^2 - 4*a^2*b^2*s^2 - 8*a^2*b*f*s^2 - 4*a^2*b*s*sin(a1) - 4*a^2*f^2*s^2 - 4*a^2*f*s*sin(a1) - a^2*sin(a1)^2)^(1/2) + 2*a^2*s - b*sin(a1) + 4*f^2*s + f*sin(a1) - 4*b*f*s)/(4*a^2*s^2 + 16*f^2*s^2 + 8*f*s*sin(a1) + sin(a1)^2)
-((4*R^2*a^2*s^2 + 16*R^2*f^2*s^2 + 8*R^2*f*s*sin(a1) + R^2*sin(a1)^2 - 4*a^2*b^2*s^2 - 8*a^2*b*f*s^2 - 4*a^2*b*s*sin(a1) - 4*a^2*f^2*s^2 - 4*a^2*f*s*sin(a1) - a^2*sin(a1)^2)^(1/2) - 2*a^2*s + b*sin(a1) - 4*f^2*s - f*sin(a1) + 4*b*f*s)/(4*a^2*s^2 + 16*f^2*s^2 + 8*f*s*sin(a1) + sin(a1)^2)
>> t=solve('(a-2*a*s*t)^2+(b+(sin(a1)+4*f*s)*t-f)^2=R^2',t)
t =
((4*R^2*a^2*s^2 + 16*R^2*f^2*s^2 + 8*R^2*f*s*sin(a1) + R^2*sin(a1)^2 - 4*a^2*b^2*s^2 - 8*a^2*b*f*s^2 - 4*a^2*b*s*sin(a1) - 4*a^2*f^2*s^2 - 4*a^2*f*s*sin(a1) - a^2*sin(a1)^2)^(1/2) + 2*a^2*s - b*sin(a1) + 4*f^2*s + f*sin(a1) - 4*b*f*s)/(4*a^2*s^2 + 16*f^2*s^2 + 8*f*s*sin(a1) + sin(a1)^2)
-((4*R^2*a^2*s^2 + 16*R^2*f^2*s^2 + 8*R^2*f*s*sin(a1) + R^2*sin(a1)^2 - 4*a^2*b^2*s^2 - 8*a^2*b*f*s^2 - 4*a^2*b*s*sin(a1) - 4*a^2*f^2*s^2 - 4*a^2*f*s*sin(a1) - a^2*sin(a1)^2)^(1/2) - 2*a^2*s + b*sin(a1) - 4*f^2*s - f*sin(a1) + 4*b*f*s)/(4*a^2*s^2 + 16*f^2*s^2 + 8*f*s*sin(a1) + sin(a1)^2)