matlab（1-x）y''=0.2sqrt(1+y'^2) 输入y=dsolve('(1-x)D2y-0.2s

来源：学生作业帮编辑：灵鹊做题网作业帮分类：数学作业时间：2024/05/16 00:54:45

matlab（1-x）*y''=0.2*sqrt(1+y'^2) 输入y=dsolve('(1-x)*D2y-0.2*sqrt(1+(Dy)^2)=0',

dsolve('(1-x)*D2y-0.2*sqrt(1+(Dy)^2)=0')
ans =
C22 + t*i
C22 - t*i
C22 - cosh(C20 - t/(5*(x - 1)))*(5*x - 5)
再问：为什么我的是 y=dsolve('5*(1-x)*D2y=sqrt(1+（Dy）^2)','y(0)=0','Dy(0)=0','x') y = Int(sinh(-1/5*log(_z1-1)+1/5*i*pi),_z1 = 0 .. x)
再答：你的符号输入有问题 y=dsolve('5*(1-x)*D2y=sqrt(1+Dy^2)','y(0)=0','Dy(0)=0','x'); simple(y) ans = (5*(-1)^(1/5)*(x - 1)^(4/5))/8 + (5*(-1)^(4/5)*(x - 1)^(6/5))/12 + 5/24 - (5*(-1)^(1/5)*(x - 1)^(4/5))/8 - (5*(-1)^(4/5)*(x - 1)^(6/5))/12 - 5/24

matlab（1-x）*y''=0.2*sqrt(1+y'^2) 输入y=dsolve('(1-x)*D2y-0.2*s 为什么在matlab中y=dsolve('5*(1-x)*D2y=sqrt+Dy*Dy)','y(0)=0,Dy(0)= >> MATLAB中Y=dsolve('int(sqrt(1+(Dy)^2=Dy*(1-x)+y))','y(0)=0, matlab求解常微分y=dsolve('D3y-3*D2y-Dy*y=0','y(0)=1 Dy(0)=-1 D2y( 用matlab解：y=dsolve('D2y+exp(-t)*Dy-sin(sqrt(t))*y=exp(-t)*sin matlab中 >> x=-1:0.001:1; >> y=log((1+sqrt(1-x.^2))/x)+sqrt(1 如何用matlab绘出函数Z=(1/(sqrt(((1-x)^2)+(y^2))))+(1/(sqrt(((1+x)^2 matlab双参数曲面怎么画fun=0.2*x/sqrt(x+x*(x-1)*y),其中0 matlab如何画y^2=sqrt(4*x.^2+1+c)-x.^2-1 用Matlab画y=sqrt(x^4+1)-10x^2 的图像 y=dsolve('D2y=(-9.8sin(y))','t')用matlab怎么解出y的轨迹? x=ln√(1+t^2),y=arctant,求d2y／d2x,注意求的是d2y/d2x 不是d2y/dx2