1/(1+√2)+1/(√2+√3)+1/(√3+√4)+.1/(√2012+√2013)
来源:学生作业帮 编辑:灵鹊做题网作业帮 分类:数学作业 时间:2024/05/11 20:23:34
1/(1+√2)+1/(√2+√3)+1/(√3+√4)+.1/(√2012+√2013)
1/(1+√2)+1/(√2+√3)+1/(√3+√4)+.1/(√2012+√2013)
=(√2-1)/(1+√2)(√2-1) + (√3-√2)/(√3+√2)(√3-√2) +(√4-√3)/(√4+√3)(√4-√3)+……+
(√2013-√2012)/(√2013+√2012)(√2013-√2012)
= √2-1 + √3 -√2 + √4 -√3 + …… + √2013 -√2012
= √2013 - 1
=(√2-1)/(1+√2)(√2-1) + (√3-√2)/(√3+√2)(√3-√2) +(√4-√3)/(√4+√3)(√4-√3)+……+
(√2013-√2012)/(√2013+√2012)(√2013-√2012)
= √2-1 + √3 -√2 + √4 -√3 + …… + √2013 -√2012
= √2013 - 1
1/(1+√2)+1/(√2+√3)+1/(√3+√4)+.1/(√2012+√2013)
二次根式题(1/√2+1+1/√3+√2+1/√4+√3+.+1/√2013+2012)(√2013 +1)= ps:+
(1/√2+√1 + 1/√3+√2 +1/√4+√3+.+1/√2010+√2009)*
计算:√4-√3/√12+√3-√2/√6+√2-√1/√2=?
|1-√2|+|√2-√3|+|√3-√4|+|√4-√5|+...+|√2009-√2010|
√(1-√2)^2+√(√2-√3)^2.+√(√99-√100)
1/√3+√2+1/√4+√3+1/√5+√4+1/√6√5
计算:√(1-√2)²+√(√2-√3)²+√(√3-√4)²+···+√(√2004-√
1 √2 √3 √6 1 √2 √3 √6 1 √2 √3 √6 1 √2 √3
请计算1/(2√1+1√2)+1/(3√2+2√3)+∧+1/[(2013√2012)+(2012√2013)]
√1+√2+√3+.+√n等于多少?
(√12-√4/3)-2(√1/8-1/√2-√18)