化简f(x)=4sinx*sin^2((π+2x)/4)+(cosx+sinx)(cosx-sinx)
化简f(x)=4sinx*sin^2((π+2x)/4)+(cosx+sinx)(cosx-sinx)
2sin(x-π/4)sin(x+π/4)=(sinx-cosx)(sinx+cosx)=-cos2a
f(x)=cos(2x-π/3)+2sin(x-π/4)怎么化简成(sinx-cosx)(sinx+cosx)
已知函数f(x)=2cosx*sin(x+π/3)-√3sin^2x+sinx*cosx
设f(x)=2cosx.sin(x+π/3)-根号3 sin平方x+sinx.cosx
sin²x/2+2sinx/2-sinx-4cosx/2=0,怎么变成(sinx/2-2cosx/2)(sin
已知函数f(x)=sinx(sinx≥cosx)cosx(cosx>sinx)
已知f(x)=sin^2+2SINX.COSX+3COSX^2
化简sin^4x/sinx-cosx - (sinx+cosx)cos^2x/tan^2x-1
a=(2cosx,sinx),b=(sin(x+3分之π),cosx-根号下3sinx),f(x)=a×b.求函数f(x
求证 sin^2x/(sinx-cosx)-(sinx+cosx)/tan^2 x-1=sinx+cosx
sinx+cosx/sinx-cosx=2 求sinx/cos^3x +cosx/sin^3x