计算：x²+2xy+y²/xy-y².x²-2xy+y²/xy+y&#

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计算：x²+2xy+y²/xy-y².x²-2xy+y²/xy+y²

[(x²+2xy+y²)/(xy-y²)][(x²-2xy+y²)/(xy+y²)]
={(x+y)²/[y(x-y)]}{(x-y)²/[y(x+y)]}
=[(x+y)(x-y)]/y²
=(x²-y²)/y²
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