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1.A function has exactly 3 zeros; they are -1,0,and 2.The fu

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1.A function has exactly 3 zeros; they are -1,0,and 2.The function passes through the point (1,6).Sketch the function,find the equation for function.
2.Find the asymptotes of the following functions.if it does not have a particular type of asymptotes(verticle,horizontal,or oblique) then briefly say why it does not.describe the end of behaviour of each function.find the intercept.draw the graph.remeber to plot a decent number of points on either side of any intercepts so your curves look reasonable.draw and label the asymptotes
a)q(x)=5x-1/x^2-2x-3
b)s(x)=3x-2/x-1
第二题看不懂的话把第一题解了就好啦,如果能解第二题更好!
1.A function has exactly 3 zeros; they are -1,0,and 2.The fu
1)f(x)=a(x+1)x(x-2)
将(1,6)带入,得a=-3
f(x)=-3x(x+1)(x-2)
图没法传,知道x正无穷时是负的,就出来了
第二问再说
2)分母为0时的x值肯定是渐近线,趋向无穷
第一个的x=-1和x=3
第二个的x=0
还有x趋向无穷时,分母为0,此时得到的直线也是渐近线
第一个的y=5x
第二个的y=3x-1