#define S(x) 4*(x)*x+1 s(4)怎么计算
#define S(x) 4*(x)*x+1 s(4)怎么计算
#define s(x) 3
求此程序的解释,就是#define s(x) 4*(x)*x+1这语句是什么意思啊,怎么运算
#define S(x)4 *(x)*x+1 main() {int k=5,j=2;printf("%d\n",S(k
#include #define S(x) x*x void main() { int a,k=3,m=1; a=S(k
求写一个scheme程序.(define (enum x e s)).
若有宏定义# define s(x) x*x-x,设int k=3; 问cout
#define f(x) x*x*x main() { int a=3,s,t; s=f(a+1);t=f((a+1))
#include #define X 5 #define Y X+1 #define Z Y*X/2 main() {
#define SETBIT(x,y) (x|=(1
C语言:二分法#include#define f(x) (x*x*x-2*x*x+3*x-4)void main(){
#define configASSERT( x )