sin50(1+根号3倍的tan10)-cos20,再整体除以cos80*根号下(1-cos20)求这个值是多少,关于三
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sin50(1+根号3倍的tan10)-cos20,再整体除以cos80*根号下(1-cos20)求这个值是多少,关于三角函数的
![sin50(1+根号3倍的tan10)-cos20,再整体除以cos80*根号下(1-cos20)求这个值是多少,关于三](/uploads/image/z/4976124-60-4.jpg?t=sin50%EF%BC%881%2B%E6%A0%B9%E5%8F%B73%E5%80%8D%E7%9A%84tan10%EF%BC%89-cos20%2C%E5%86%8D%E6%95%B4%E4%BD%93%E9%99%A4%E4%BB%A5cos80%2A%E6%A0%B9%E5%8F%B7%E4%B8%8B%EF%BC%881-cos20%EF%BC%89%E6%B1%82%E8%BF%99%E4%B8%AA%E5%80%BC%E6%98%AF%E5%A4%9A%E5%B0%91%2C%E5%85%B3%E4%BA%8E%E4%B8%89)
(sin50°(1+√3*tan10°)-cos20°)/(cos80°*√(1-cos20°))
=(sin50°(1+√3*sin10°/cos10°)-cos20°)/(cos80°*√(1-cos20°))
=(sin50°((cos10°+√3*sin10°)/cos10°)-cos20°)/(cos80°*√(2(sin10°)^2))
=(sin50°((1/2)cos10°+(√3/2)*sin10°)/((1/2)*cos10°)-cos20°)/(cos80°*√(2(sin10°)^2))
=(sin50°(sin30°*cos10°+cos30°*sin10°)/(1/2)*cos10°-cos20°)/((√2)cos80°*sin10°)
=(sin50°*sin40°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=(sin50°*cos50°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)sin100°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)sin80°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)cos10/(1/2)*cos10°-cos20°)/((√2)sin10°sin10°)
=(1-cos20°)/((√2)sin10°sin10°)
=2(sin10°)^2/(√2)(sin10°)^2
=2/√2
=√2
=(sin50°(1+√3*sin10°/cos10°)-cos20°)/(cos80°*√(1-cos20°))
=(sin50°((cos10°+√3*sin10°)/cos10°)-cos20°)/(cos80°*√(2(sin10°)^2))
=(sin50°((1/2)cos10°+(√3/2)*sin10°)/((1/2)*cos10°)-cos20°)/(cos80°*√(2(sin10°)^2))
=(sin50°(sin30°*cos10°+cos30°*sin10°)/(1/2)*cos10°-cos20°)/((√2)cos80°*sin10°)
=(sin50°*sin40°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=(sin50°*cos50°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)sin100°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)sin80°/(1/2)*cos10°-cos20°)/((√2)sin10°*sin10°)
=((1/2)cos10/(1/2)*cos10°-cos20°)/((√2)sin10°sin10°)
=(1-cos20°)/((√2)sin10°sin10°)
=2(sin10°)^2/(√2)(sin10°)^2
=2/√2
=√2
sin50(1+根号3倍的tan10)-cos20,再整体除以cos80*根号下(1-cos20)求这个值是多少,关于三
(sin50(1+根号3*tan10)-cos20)/cos80根号(1-cos20)
【跪求】【求值】(sin50(1+根号(3)*tan10)-cos20)\(根号(2)*cos80*sin10)
求值:【sin50°[1+根号(3)tan10°]—cos20°】/[cos80°根号(1—cos20°)】
sin50度(1+根号3tan10度)-cos20度/cos80度根号1-cos20度=
求值:[sin50°(1+tan10°√3)-cos20°]/[cos80°乘以根号下1-cos20°]
cos80度根号1-cos20度分之sin50度(1+根号3tan10度)-cos20度=
化简:【sin50°·(1+√3tan10° )-cos20°】/(cos80°· √1-cos20°)
化简sin50°(1+√3tan10°)-cos20°/cos80°√(1-cos20°)
化简:sin50º(1+√3tan10°)-cos20°/cos80°√(1-cos20°)
化简{2sin50°+sin10°【1+(根号3tan10°)】根号(1加cos20)°
化简sin50度(1+根号3倍tan10度)