求第十题演算过程!
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求第十题演算过程!
![求第十题演算过程!](/uploads/image/z/4238829-45-9.jpg?t=%E6%B1%82%E7%AC%AC%E5%8D%81%E9%A2%98%E6%BC%94%E7%AE%97%E8%BF%87%E7%A8%8B%21%26nbsp%3B)
multiply ...by 2
divide both sides of the equation by m
cancel out m on the right hand side
take the square root of both sides
Get the final expression for v
再问:![](http://img.wesiedu.com/upload/7/e7/7e702e624aa24646323621e32e9a6025.jpg)
再问: 怎么
再问: 做
再答: a. C = 250 + 15n b. C(50) = 1000, C(100) = 1750 c. n = (C-250)/15 d. n(4000) = (4000-250)/15 = 250, n(2000) = 116 (take whole number) e. rearranged formula is easier to use. Otherwise, you would have 4000 = 250 + 15n, and then work out n f. C is a linear function of n as when n increases, the cost C increases proportionally
再问: thanks
再问: 《diary of a wimpy kid》
再问: In the book, what are the problems about teen?
再问: 急急急急
再问: Find the length of time it takes for the vibration to travel from shot point back to the surface
再问:![](http://img.wesiedu.com/upload/3/0d/30d6f0e96cbaf0936ff545b1da3de7d9.jpg)
再问: 帮帮我!
再问: 2.Given that the vibration ( ray path ) comes out of the surfaces 150 m away from the shot point, what is the total length of the ray path? Use the above diagram and a formula to solve. The triangles, on either side of the dashed line, are equal.
再答: The path length = 2 square root of (10^2 + 75^2) = 151. meters
再问: thanks
divide both sides of the equation by m
cancel out m on the right hand side
take the square root of both sides
Get the final expression for v
再问:
![](http://img.wesiedu.com/upload/7/e7/7e702e624aa24646323621e32e9a6025.jpg)
再问: 怎么
再问: 做
再答: a. C = 250 + 15n b. C(50) = 1000, C(100) = 1750 c. n = (C-250)/15 d. n(4000) = (4000-250)/15 = 250, n(2000) = 116 (take whole number) e. rearranged formula is easier to use. Otherwise, you would have 4000 = 250 + 15n, and then work out n f. C is a linear function of n as when n increases, the cost C increases proportionally
再问: thanks
再问: 《diary of a wimpy kid》
再问: In the book, what are the problems about teen?
再问: 急急急急
再问: Find the length of time it takes for the vibration to travel from shot point back to the surface
再问:
![](http://img.wesiedu.com/upload/3/0d/30d6f0e96cbaf0936ff545b1da3de7d9.jpg)
再问: 帮帮我!
再问: 2.Given that the vibration ( ray path ) comes out of the surfaces 150 m away from the shot point, what is the total length of the ray path? Use the above diagram and a formula to solve. The triangles, on either side of the dashed line, are equal.
再答: The path length = 2 square root of (10^2 + 75^2) = 151. meters
再问: thanks