int x[5]={1,2,3,4,5,},y[5];错在哪?
int x[5]={1,2,3,4,5,},y[5];错在哪?
1)int z=5;f ( ){ static int x=2; int y=5;x=x+2; z=z+5;y=y+z;
fun(int x,int y,int z) {z=x*x+y*y;} main() {int a=31; fun(5,
1 int x=1,y=0; 2 if(!x) y++; 3 else if(x==0) 4 if(x) y+=2; 5
int x=5; int y=2+(x+=x++,x+8,++x); printf("%d",y); 结果是多少,为什么
int x=-5,y;cout
#include Int main(void ) { int a = 5,b = 4,x,y; x = 2 * a++
Struct Struct st {int x;int *y;}*pt; Int a[]={1,2},b[]={3,4}
int x,y; x=13; y=5; {printf("%d",x%=(y/=2));
若定义:int x=3,y=4,z=5; 那么表达式 (x+y)+z-1&&y+z/2的值?1
int x=3,y=4,z=5;则表达式 (x+y)+2-1&&y+z/2的值
已有定义:int x=3,y=4,z=5;,则表达式!(x+y)+z-1&&y+z/2的值为,