电路及参数如图,用戴维宁定理求电流
来源:学生作业帮 编辑:灵鹊做题网作业帮 分类:数学作业 时间:2024/06/18 00:20:29
电路及参数如图,用戴维宁定理求电流
![](http://img.wesiedu.com/upload/f/d8/fd8fc45502be8531808c1d5bb548b182.jpg)
![](http://img.wesiedu.com/upload/f/d8/fd8fc45502be8531808c1d5bb548b182.jpg)
![电路及参数如图,用戴维宁定理求电流](/uploads/image/z/2928901-13-1.jpg?t=%E7%94%B5%E8%B7%AF%E5%8F%8A%E5%8F%82%E6%95%B0%E5%A6%82%E5%9B%BE%2C%E7%94%A8%E6%88%B4%E7%BB%B4%E5%AE%81%E5%AE%9A%E7%90%86%E6%B1%82%E7%94%B5%E6%B5%81)
![](http://c.hiphotos.baidu.com/zhidao/wh%3D600%2C800/sign=e14238274d4a20a4314b34c1a062b41a/79f0f736afc37931a801e61ce9c4b74543a9119d.jpg)
12V 、6Ω ,18V、3Ω 变换成电流源形式,合并 1A 电流源:Is = 12/6 + 18/3 - 1 = 7 ARs = 6 // 3 = 2 Ω再转回电压源,合并 6V 电压源:Us = 7 * 2 + 6 = 20 VRs = 2 Ω
![](http://img.wesiedu.com/upload/b/3f/b3fee09e31cbe3da9ddffb00370422b2.jpg)
= 15 VRab = 2 // 6 + 1 = 2.5 ΩI = Uab / (Rab + 3) = 15 / 5.5 = 2.73 A