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先化简,再求值,先化简,再求值,【1/(x-y)】-【1/(x+y)】/【xy²/(x²-y

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先化简,再求值,
先化简,再求值,【1/(x-y)】-【1/(x+y)】/【xy²/(x²-y²)】,其中x=√2+1,
y=√2-1
先化简,再求值,先化简,再求值,【1/(x-y)】-【1/(x+y)】/【xy²/(x²-y
先化简,再求值:【1/(x-y)】-【1/(x+y)】/【xy²/(x²-y²)】,其中x=√2+1,
y=√2-1
【1/(x-y)】-【1/(x+y)】/【xy²/(x²-y²)】
=(x+y-x+y)/(x^2-y^2)*(x^2-y^2)/(xy^2)
=2y/(xy^2)
=2/(xy)
=2/(√2+1)(√2-1)
=2 .
再问: 【1/(x-y)】-【1/(x+y)】/【xy²/(x²-y²)】 =(x+y-x+y)/(x^2-y^2)*(x^2-y^2)/(xy^2) 这一步的(x+y-x+y)/(x^2-y^2)怎么来的,我怎么弄不出来
再答: x-y 、x+y 是分母,公分母是:x^2-y^2 1/(x-y)=(x+y)/(x^2-y^2) 1/(x+y)=(x-y)/(x^2-y^2) 1/(x-y)-1/(x+y) =(x+y)/(x^2-y^2)-(x-y)/(x^2-y^2) =(x+y-x+y)/(x^2-y^2)
再问: 不是要先算后面那两个除的再和前面勉这个相减吗
再答: 那是我搞错了,应该要先算后面那两个除的,再和前面这个相减!
再问: 所以你要不要再算一下
再答: 先化简,再求值:【1/(x-y)】-【1/(x+y)】/【xy²/(x²-y²)】,其中x=√2+1, y=√2-1 【1/(x-y)】-【1/(x+y)】/【xy²/(x²-y²)】 =1/(x-y)-(x-y)/(x^2-y^2)*(x^2-y^2)/(xy^2) =1/(x-y)-(x-y)/(xy^2) =1/(√2+1-√2+1)-(√2+1-√2+1)/[(√2+1)(√2-1)^2] =1/2-2/(√2-1) =1/2-2(√2+1) =1/2-2-2√2 =-1.5-2√2 .