求两条因式分解答案 1.已知2x^2-5x+1=-1及xy^2=3,求8x^3y^2-20x^2y^2+4xy^2
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求两条因式分解答案 1.已知2x^2-5x+1=-1及xy^2=3,求8x^3y^2-20x^2y^2+4xy^2
1.已知2x^2-5x+1=-1及xy^2=3,求8x^3y^2-20x^2y^2+4xy^2的值
2.已知x^2-3x+1=2及xy=7,求6x^2y-2x^3y-2xy的值
1.已知2x^2-5x+1=-1及xy^2=3,求8x^3y^2-20x^2y^2+4xy^2的值
2.已知x^2-3x+1=2及xy=7,求6x^2y-2x^3y-2xy的值
![求两条因式分解答案 1.已知2x^2-5x+1=-1及xy^2=3,求8x^3y^2-20x^2y^2+4xy^2](/uploads/image/z/2069895-39-5.jpg?t=%E6%B1%82%E4%B8%A4%E6%9D%A1%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E7%AD%94%E6%A1%88+1.%E5%B7%B2%E7%9F%A52x%5E2-5x%2B1%3D-1%E5%8F%8Axy%5E2%3D3%2C%E6%B1%828x%5E3y%5E2-20x%5E2y%5E2%2B4xy%5E2)
1、8x^3y^2-20x^2y^2+4xy^2
=4xy²(2x²-5x+1)
=4×3×(-1)
=-12
2、6x^2y-2x^3y-2xy
=2xy(3x-x²-1)
=2×7×[-(x²-3x+1)]
=14×(-2)
=-28
=4xy²(2x²-5x+1)
=4×3×(-1)
=-12
2、6x^2y-2x^3y-2xy
=2xy(3x-x²-1)
=2×7×[-(x²-3x+1)]
=14×(-2)
=-28
求两条因式分解答案 1.已知2x^2-5x+1=-1及xy^2=3,求8x^3y^2-20x^2y^2+4xy^2
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