若数列an满足a1=1,an+1(+1下标)=1/2an + 1(1/2an与+1分开),求an
数列{an},a1=2,an+1(下标)=an下标+n+1 求通项an下标
一直数列{an}满足a1=0,an=(an-1 +4)/(2an-1) ,求 an
数列{an}满足a1=1,且an=an-1+3n-2,求an
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
数列an满足a1=2,an+1=an²求an
已知数列{an}满足a1=1,an+1=2an+1 1)求证:数列{an+1}为等比数列; 2) 求{an}的通项an
数列{an}满足a1=1,an=an-1(1+2an)(n-1是下标).1、求证:{1/an}是等差数列;2、若a1a2
已知数列an中 a1=-2且an+1=sn(n+1为下标),求an,sn
已知在数列{an}中,a1=2,an=3a[(n-1)](下标)-2,求an
若数列{An}满足An+1=An^2,则称数列{An}为“平方递推数列”,已知数列{an}中,a1=9,点(an,an+
已知数列(an)满足an+1=2an+3×2∧n,a1=2求an
已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an