数列an-an-1=2(n>=2)要检验a1吗
设数列{an},a1=3,an+1=3an-2(n∈N*)
数列{an}满足a1=1 an+1=2n+1an/an+2n
数列{an},a1=1,an+1=2an-n^2+3n,求{an}.
已知数列{an}满足:a1=3,an+1=(3an-2)/an ,n∈N*.(Ⅰ)证明数列{(an-1)/an-2
已知数列{An}满足:A1=3 ,An+1=(3An-2)/An,n属于N*.1)证明:数列{(An--1)/(An--
一直数列{An}满足A1=1/2,A1+A2+…+An=n^2An
设b>0,数列an满足a1=b,an=nban-1/an-1+n-1(n≥2)求数列an通向公式.
设b>0,数列an满足a1=b,an=nban-1/an-1+n-1(n≥2)求数列an通向公式
已知数列{an}中,a1=2,an+1=an²+2an(n∈N+)
设数列{an}中,a1=2,an+1=an+n+1,则通项an=?
在数列an中,a1=2 an+1=an+3n则an=
数列{an},a1=2,an+1(下标)=an下标+n+1 求通项an下标