数列{an}满足a1=2,且3an+1—an=0,则a4是多少?
数列{an}满足a1=1,且an=an-1+3n-2,求an
已知数列{an}满足:a1=1,且an-an-1=2n,求(1)a2,a3,a4.(2)求数列{an}的通项an
已知数列{an}满足a1=2且anan+1-2an=0球a2,a3,a4的值
已知数列{an}满足:a1=1,且an-a(n-1)=2n.求a2,a3,a4.求数列{an}通项an
数列{an}中,a1=8,a4=2且满足an+2=2an+1-an( n∈N*)
已知数列{an}中,a1=8,a4=2,且满足an+2-2an+1+an=0 (n∈N),求数列{an}的通项公式;设S
已知数列{an}中,a1=8,a4=2,且满足an+2-2an+1+an=0 (n∈N),求数列{an}的通项公式
【高中数学数列】已知数列an满足a1=1,a2=2,且an=an-1/an-2 (n大于等于3)则a2012=?
数列an满足a1=2,an+1=4an+9,则an=?
若数列{An}满足An+1=An^2,则称数列{An}为“平方递推数列”,已知数列{an}中,a1=9,点(an,an+
已知数列{an}满足An+1=2^nAn,且A1=1,则通项an
已知数列an满足an=1+2+...+n,且1/a1+1/a2+...+1/an