若sin(α-360°)-cos(180°-α)=m,则sin(180°+α)·cos(180°-α)等于
若sin(α-360°)-cos(180°-α)=m,则sin(180°+α)·cos(180°-α)等于
Cos(180°+α)*sin(α+360°)/sin(-α-180°)*cos(-180°-α)
已知cos(180°+α)=-3/5,则sin(360°-α)的值等于
.[1/cos(-α)+cos(180°+ α )]/[1/sin(540°-α)+sin(360°-α)]=tan^3
已知sin(360°+α)-cos(180°-α)=m
化简cos(540°-α)sin(α-360°)/sin(-α+180°)cos(180°+α)
已知sin(a-360°)-cos(180°-a)=m,则sin(180°+a)*cos(180°-a)等于?
若sin(α+β)sin(β-α)=m,则(cosα)^2-(cosβ)^2等于?
若sinα+cosα=m,则sinα-cosα=____.(0°<α<45°)
若sinα+cosα=根号2,则sinα-cosα的值等于?
求证:(1/sinα-sin(180°+α))/(1/cos(540°-α)+cos(360°-α))=1/(tanα)
化简sin(α+180°)cos(-α)sin(-α-180°)