set talk off clear for W=100to 200 prime=.t. for I=2to W-1 i
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set talk off clear for W=100to 200 prime=.t. for I=2to W-1 if mod(W,I)=0 prime=.f. exit endif enddo
哪里错掉了.嵌套错误又是什么.不是很懂
若改为任意范围内的素数和(100与200用m,n代替呢.该怎么写)
非常感谢.
机试后输出的是f
不是很董。。为什么是.f..假如要求100到200内的素数的和呢?
哪里错掉了.嵌套错误又是什么.不是很懂
若改为任意范围内的素数和(100与200用m,n代替呢.该怎么写)
非常感谢.
机试后输出的是f
不是很董。。为什么是.f..假如要求100到200内的素数的和呢?
上面的命令缺少内容,下面是正确的:
set talk off
clear
for w=100 to 200
prime=.t.
for i=2 to w-1
if mod(w,1)=0
prime=.f.
exit
endif
endfor
endfor
prime
解析:for后面是赋值变量,比如w=100,就是将100赋给w,to后面是终值,当w
set talk off
clear
for w=100 to 200
prime=.t.
for i=2 to w-1
if mod(w,1)=0
prime=.f.
exit
endif
endfor
endfor
prime
解析:for后面是赋值变量,比如w=100,就是将100赋给w,to后面是终值,当w
set talk off clear for W=100to 200 prime=.t. for I=2to W-1 i
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