计算:(1)2/(x+y)+4y/x²-y²(2)x²/x+y-x+y
计算:(1)2/(x+y)+4y/x²-y²(2)x²/x+y-x+y
x(x-y)-y(y-x)+(x-y)²因式分解
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
因式分解x²(x-2y)+y²(2y-x)
计算 x+2y+﹙4y²/x-2y﹚+﹙4x²y/4y²-x²)
{(x-y)²+(x+y)(x-y)}÷2x
计算:[(x+¼y)+(x-¼y)](2x²-1/8y²)
计算:(4y分之3x²)² × 3x分之2y + 2y²分之x² ÷ x分之2y
(2x+y)²-y(y+4x)-8x等于?
(x-2y)²+(2x-4y)(x+y)+(x+y)²
计算4(x+y)^5(x-y)^4÷[2(x+y)³*(y-x)²]
运用乘法公式计算:(1)(x-y)(x+y)-(2x-y)²