sin(3π/2-2x)=3/5 求tan²x
sin(3π/2-2x)=3/5 求tan²x
三角函数题.已知tanx=2.求(sin(π-x)cos(2π-x)sin(-x+3π/2))/tan(-x-π)sin
已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x
已知sinα是方程5x²-7x-6=0的根,求[sin(-α+3π/2)sin(π-α)tan²(2
已知2tanx/(1+tan^2x)=3/5,求sin^2(π/4+x)的值
急. .已知cos(π/4+x)=3/5,5/4π<x<7π/4,求(sin2x+2sin²x)/(1-tan
若tanx=2,求:sin(tt/2+x)*cos(tt/2-x)*tan(-x+3tt)/sin(7tt-x)*tan
已知sinx=3/5,求sin(x-3/2派cos(派-x)tan(派+x)
已知方程2x²-(根号3+1)x+m=0的两个根分别为sinθ,cosθ,求[sin(π-θ)×tan(π+θ
已知sin(x+2y)=3sinx,求tan(x+y)*coty
求不定积分 (1)((tan x)^2+(tan x)^4) (2)(1/(1+sin x) dx (3) 1/(2x^
sin(x+y)=1\2,sin(x—y)=1\3,求[tan(x+y)-tanx-tany]\[tany的平方tan(