层次分析法matlab程序运行后结果怎样理解?

层次分析法matlab程序运行后结果怎样理解?
下面是代码：
clc
a=[1,1,1,4,1,1/2
1,1,2,4,1,1/2
1,1/2,1,5,3,1/2
1/4,1/4,1/5,1,1/3,1/3
1,1,1/3,3,1,1
2,2,2,3,3,1];%一致矩阵
[x,y]=eig(a);eigenvalue=diag(y);lamda=max(eigenvalue);
ci1=(lamda-6)/5;cr1=ci1/1.24
w1=x(:,1)/sum(x(:,1))
b1=[1,1/4,1/2;4,1,3;2,1/3,1];
[x,y]=eig(b1);eigenvalue=diag(y);lamda=eigenvalue(1);
ci21=(lamda-3)/2;cr21=ci21/0.58
w21=x(:,1)/sum(x(:,1))
b2=[1 1/4 1/5;4 1 1/2;5 2 1];
[x,y]=eig(b2);eigenvalue=diag(y);lamda=eigenvalue(1);
ci22=(lamda-3)/2;cr22=ci22/0.58
w22=x(:,1)/sum(x(:,1))
b3=[1 3 1/3;1/3 1 1/7;3 7 1];
[x,y]=eig(b3);eigenvalue=diag(y);lamda=eigenvalue(1);
ci23=(lamda-3)/2;cr23=ci23/0.58
w23=x(:,1)/sum(x(:,1))
b4=[1 1/3 5;3 1 7;1/5 1/7 1];
[x,y]=eig(b4);eigenvalue=diag(y);lamda=eigenvalue(1);
ci24=(lamda-3)/2;cr24=ci24/0.58
w24=x(:,1)/sum(x(:,1))
b5=[1 1 7;1 1 7;1/7 1/7 1];
[x,y]=eig(b5);eigenvalue=diag(y);lamda=eigenvalue(1);
ci25=(lamda-3)/2;cr25=ci25/0.58
w25=x(:,1)/sum(x(:,1))
b6=[1 7 9;1/7 1 1 ;1/9 1 1];
[x,y]=eig(b6);eigenvalue=diag(y);lamda=eigenvalue(1);
ci26=(lamda-3)/2;cr26=ci26/0.58
w26=x(:,1)/sum(x(:,1))
w_sum=[w21,w22,w23,w24,w25,w26]*w1
ci=[ci21,ci22,ci23,ci24,ci25,ci26];
cr=ci*w1/sum(0.58*w1)
下面是运行后的结果：
cr1 = 0.0996
w1 = 0.1507 0.1792 0.1886 0.0472 0.1464 0.2879
cr21 =0.0158
w21 =0.1365 0.6250 0.2385
cr22 = 0.0212
w22 =0.0974 0.3331 0.5695
cr23 = 0.0061
w23 = 0.2426 0.0879 0.6694
cr24 = 0.0559
w24 =0.2790 0.6491 0.0719
cr25 =-1.1485e-015
w25 =0.4667 0.4667 0.0667
cr26 =0.0061
w26 =0.7986 0.1049 0.0965
w_sum = 0.3952 0.2996 0.3052
cr =0.0117
cr代表什么?w25又代表什么?

%层次分析法的matlab程序
disp('请输入判断矩阵A(n阶)');
A=input('A=');
[n,n]=size(A);
x=ones(n,100);
y=ones(n,100);
m=zeros(1,100);
m(1)=max(x(:,1));
y(:,1)=x(:,1);
x(:,2)=A*y(:,1);
m(2)=max(x(:,2));
y(:,2)=x(:,2)/m(2);
p=0.0001;i=2;k=abs(m(2)-m(1));
while k>p
i=i+1;
x(:,i)=A*y(:,i-1);
m(i)=max(x(:,i));
y(:,i)=x(:,i)/m(i);
k=abs(m(i)-m(i-1));
end
a=sum(y(:,i));
w=y(:,i)/a;
t=m(i);
disp('权向量');disp(w);
disp('最大特征值');disp(t);
%以下是一致性检验
CI=(t-n)/(n-1);RI=[0 0 0.52 0.89 1.12 1.26 1.36 1.41 1.46 1.49 1.52 1.54 1.56 1.58 1.59];
CR=CI/RI(n);
if CR<0.10
disp('此矩阵的一致性可以接受!');
disp('CI=');disp(CI);
disp('CR=');disp(CR);
else
disp('此矩阵的一致性不可以接受!');
end