|xy-3| (x-2y 2)²=0 ,x²-3xy 4y²

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 16:14:15
|xy-3| (x-2y 2)²=0 ,x²-3xy 4y²
化简(x-yx2-2xy+y2-xy+y2x2-y2)•xyy-1= ___ .

原式=[x-y(x-y)2-y(x+y)(x+y)(x-y)]•xyy-1=(1x-y-yx-y)•xyy-1=1-yx-y•xyy-1=-xyx-y.故答案是:-xyx-y.

已知(x+y)2=25,xy=3,求x2+y2求x2+y2的值答案是?

解(x+y)²=25∴x²+2xy+y²=25∵xy=3∴x²+y²+6=25∴x²+y²=19

x(x-1)-(x2-y)=-3,求x2-y2-2xy的值

解题思路:由完全平方公式可求解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/rea

已知x2-2xy=3y2且x,y为非零实数 求:(1)2x+y/x-2y (2)2x2-3y2+5xy/x2+xy+y2

∵x²-2xy-3y²=0∴*(x-3y)(x+y)=0∴x=3y或x=-y(1)2x+y/x-2y当x=3y时,原式=7y/y=7当x=-y时,原式=y/(-3y)=-1/3(2

若x2+xy-2y2=0,则x

由x2+3xy+y2 x2+y2有意义,可知y与x不能同时为0.不妨设y≠0,由x2+xy-2y2=0,化为(x+2y)(x-y)=0,解得x=y,或x=-2y.把x=y代入,可得x2+3x

先化简,再求值:(1)2x2-5x x2 4x,其中x=-3 (2)(3x2-xy-2y2)-2(x2 xy-2y2),

:(1)2x2-5x+x2+4x,其中x=-3=3x²-x=3x(-3)²+3=27+3=30(2)(3x2-xy-2y2)-2(x2+xy-2y2),其中x=6,y=-1=3x&

已知2x-3*根号(xy)-2y=0(x>0),则x2+4xy-16y2除以2x2+xy-9y2的值是多少?

已知2x-3*根号(xy)-2y=0(x>0),则x2+4xy-16y2除以2x2+xy-9y2的值是多少?2x-3*根号(xy)-2y=0(根号X-2根号Y)(2根号X+根号Y)=0根号X-2根号Y

已知x+y=4,xy=2,则x2+y2+3xy=______.

x2+y2+3xy=(x+y)2+xy,∵x+y=4,xy=2,∴x2+y2+3xy=42+2=18.故答案为18.

已知2x=3y,求xy/(x2+y2)-y2/(x2-y2)的值

已知2x=3y,求xy/(x^2+y^2)-y^2/(x^2-y^2)的值2x=3y-->x=(3/2)yx^2=(9/4)y^2xy/(x^2+y^2)-y^2/(x^2-y^2)==(3/2)y*

先化简,再求值:(-3xy)2(x2+xy-y2)-3x2y2(3x2+3xy+y2),其中x=-43

原式=9x2y2(x2+xy-y2)-3x2y2(3x2+3xy+y2)=9x4y2+9x3y3-9x2y4-9x4y2-9x3y3-3x2y4=-12x2y4,当x=-43,y=-32时,原式=-1

已知x+y=4,x-y=6,化简xy(y2+y)-y2(xy+2x)-3xy,并求它的值.

原式=xy3+xy2-xy3-2xy2-3xy=-xy2-3xy,由x+y=4,x-y=6可知:x=5,y=-1,把x=5,y=-1代入,原式=10.

先化简再求值:-(x2+y2)+[-3xy-(x2-y2)],其中x=-1,y=2.

原式=-x2-y2-3xy-x2+y2=-2x2-3xy,当x=-1,y=2时,原式=-2×(-1)2-3×(-1)×2=4.

x(x-1)-(x2-y)=-3,求x2+y2-2xy的值

x(x-1)-(x2-y)=-3x2-x-x2+y=-3-x+y=-3所以x-y=3所以原式=(x-y)2=9

x2-2xy+y2+3x-3y+2.

x2-2xy+y2+3x-3y+2=(x-y)2+3(x-y)+2=(x-y-1)(x-y-2).

已知x(x-1)-(x2-y)=-3,求x2+y2-2xy的值

解题思路:完全平方公式解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.

已知x+y=4,xy=2,求x2+y2+3xy的值.

∵x+y=4,xy=2,∴x2+y2+3xy,=(x+y)2+xy,=42+2,=18.

已知实数x、y满足2x2-7xy+3y2=0,求x:y

分解因式有(x-3y)(2x-y)=0所以有x=3y或2x=y所以x:y=3:1或x:y=1:2

已知:x=3,y=-5,x2-2xy+y2/x2-y2的值是

x²-2xy+y²/x²-y²=(x-y)²/(x-y)(x+y)=(x-y)/(x+y)因为x=3,y=-5,所以(3-(-5))/(3+(-5))

已知实数x,y满足x2+xy+y2=3,则x2-xy+y2的最小值

由x2+xy+y2=3得,x^2+y^2=3-xyx^2+y^2≥2xy得,xy≤1所以x^2-xy+y^2=3-2xy≥1等号成立当且仅当x=y=±1

已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以(x2+y2/x

因为x²+4y²+x²y²-6xy+1=0(x²-4xy+4y²)+(x²y²-2xy+1)=0(x-2y)²