y-2y y=1 x x^2通解

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y-2y y=1 x x^2通解
(x-y)(x+y)(xx-yy)=?

(x-y)(x+y)(xx-yy)=(x^2-y^2)(x^2-y^2)=x^4-2x^2y^2+y^4

已知14(XX+YY+ZZ)=(X+2Y+3Z)^2,求X:Y:Z

X:Y:Z=1:2:3因为:14(XX+YY+ZZ)=(X+2Y+3Z)^214(XX+YY+ZZ)-(X+2Y+3Z)^2=013X^2+10Y^2+5Z^2-4XY-6XZ-12YZ=0(4X^2

已知x,y是实数,且适合方程(xx+xy-12)(xx+xy-12)+(xy-2yy-1)(xy-2yy-1)=0求x,

(x²+xy-12)²+(xy-2y²-1)²=0由于平方数都大于或等于0,所以上式成立的前提是:(x²+xy-12)²=0,即:x&sup

设x=1/(√3-2),y=1/(√3+2)求代数式 (xx+xy+yy)/(x+y) 的值》

x=1/(√3-2)=-(2+√3)y=1/(√3+2)=2-√3x+y=-2√3xy=-1xx+xy+yy=(x+y)^2-xy=12-(-1)=13(xx+xy+yy)/(x+y)=-13/2√3

已知xx+xy=1,xy-yy=-4,则xx+2xy-yy=

xx+2xy-yy=-3两式相加即可

二维等高线 k=2*((1-xx.^2).*(1-yy.^2)-sqrt(1-xx.^2).*sqrt(1-yy.^2)

a+b=(y-x)+(2x-y)=x2a+b=(2y-2x)+(2x-y)=y.(2)cost=x.y/(|x||y|)由a⊥b知a.b=0.x.y=(a+b).(2a+b)=a.2a+b.b=2+1

1:是俩个构造函数么?2:public Point(int xx,int yy){setPoint(xx,yy);}是什

是2个构造函数.一个默认的不带参.一个带参.带参的接受2个参数.在调用setPoint给x,y赋值再问:为什么方法serPoint是一个参数?而构造方法确实俩个参数?(XX,YY)再答:publicv

已知2x=3y,求xy/xx+yy-yy/xx-yy的值

2/9再问:过程,谢谢再答:由题目得y/x=2/3xy/xx+yy-yy/xx-yy=y/x-(y/x)²=2/3-4/9=2/9

已知x=1/2 y=1/3 z=1/4 则(xx+yy-zz+2xy)/(xx-yy+zz-2xz) 得多少?

x2+y2-z2+2xy/x2-y2+z2-2xz=(x+y)2-z2/(x-z)2-y2=(x+y-z)(x+y+z)/(x-y-z)(x-z+y)=(x+y+z)/(x-y-z)然后就是代入了

((xx+yy)/y-2y)/(1/y-1/x)^(1/(xx-yy))

原式=[(x²+y²-2y²)/y]/[(x-y)/xy]×1/(x²-y²)=[(x²-y²)/y]×[xy/(x-y)]×1/

已知xx+yy+4x-6y+13=0,求(xx-2x)/xx+3yy的值.

xx+yy+4x-6y+13=0整理得:(x+2)^2+(y-3)^2=0那么只有(x+2)=0(y-3)=0x=-2y=3(x^2-2x)/(x^2+3y^2)=(4+4)/(4+3*9)=8/31

已知x(x+1)-(xx+y)=3,求(xx+yy)/2-xy的值

x^2+x-x^2-y=3x-y=3(x-y)^2=9x^2+y^2-2xy=9(x^2+y^2)/2-xy=9/2

已知(XX+YY—2)(XX+YY)=3,求XX+YY

令a=XX+YY则(a-2)a=3a²-2a-3=0(a-3)(a+1)=0a=3,a=-1因为XX+YY≥0所以XX+YY=3

求y''=1+y'^2通解...

y=C2-ln[cos[x+C1]]dy'/dx=1+(y')^2dy/(1+(y')^2)=dxArcTan(y')=x+C1y'=Tan(x+C1)dy=Tan(x+C1)dxy=C2-ln[co

若(xx)+(yy)-4x+6y+13=0,求2x+3y的值?

(xx)+(yy)-4x+6y+13=0(xx)-4x+(yy)+6y+13=0(xx)-4x+4+(yy)+6y+9=0(x-2)²+(y+3)²=0x-2=0y+3=0x=2y

已知 xx-2x+yy+6y+10=0 求x+y的值

x^2-2x+y^2+6y+10=0(x-1)^2+(y+3)^2=0所以x=1,y=-3x+y=-2x^2表示x的平方

x(x+1)-(xx+y)=-3,求(xx+yy)/2-xy的值

x(x+1)-(xx+y)=-3x^2+x-x^2-y=-3x-y=-3(xx+yy)/2-xy=(x^2+y^2-2xy)/2=(x-y)^2/2=(-3)^2/2=9/2再问:是对的吧!再答:当然

已知x-y=2,(xx)-(yy)=12,求x与y的值

方程组:X-Y=2……①X^2-Y^2=12……②②÷①得X+Y=6……③①+③得:2X=8,X=4,把X=4代入③得:Y=2,X=4Y=2