若y=ln(4 x^2),试求y的凹凸区间及拐点-搜答案-灵鹊做题网

设y=ln ln ln x,求y’

y'=(lnlnx)'/lnlnx=(lnx)'/lnxlnlnx=1/xlnxlnlnx

y=x^5+ln^3x 求y'

y=x^5+ln^3xy'=（x^5）’+（ln^3x）‘=5x^4+3(lnx)²/X

等式两边同时求导得:2y*y'+y'/y=4*x^3-->y'=4y*x^3/(2y^2+1)y'=dy/dx-->dy=y'*dx=dx*4y*x^3/(2y^2+1)

y=ln(1+x^2),求y

y'=[1/(1+x^2)]*(1+x^2)'=[1/(1+x^2)]*2x=2x/(1+x^2)

求导y=ln ln ln(x^2+1)

y=ln[ln(ln x)] 求导

复合函数f(x)=lnxg(x)=ln[ln(x)]r(x)=ln{lnln(x)]}r'(x)=[1/lnln(x)]g'(x)=[1/lnln(x)][1/ln(x)]f'(x)=[1/lnln(

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y=ln[x(2x+1)]=ln(2x^2+x)所以：y'=[1/(2x^2+x)]*(2x^2+x)'=[1/(2x^2+x)]*(4x+1)=(4x+1)/(2x^2+x).如果是：y=lnx*(

x/y=ln(y/x)x(-1/y^2)y'+1/y=x/y(-y/x^2+y'/x)(1/y+x/y^2)y'=1/y+1/x[(y+x)/y^2]y'=(x+y)/xyy'=y/x

y=ln(x+x^2) 求dy

y'=1/(x+x^2)*(2x+1)=(2x+1)/(x+x^2)dy=(2x+1)/(x+x^2)dx

y=(ln(ln(x))'/ln(ln(x))=(ln(x))'/(ln(x)(ln(ln(x)))=1/(xln(x)ln(ln(x)))

混合求导问题

y=ln(x^2+2)是复合函数所以y'=[ln(x^2+2)]'[x^2+2]'=[1/(x^2+2)][2x]=2x/(x^2+2)

y=ln(1-x^2) 求y''

y=ln(1-x^2)y'=(1-x^2)'/(1-x^2)=-2x/(1-x^2)

y=ln(ln平方x),求dy

y=2ln(lnx)dy=y'dx=(2/lnx)*(1/x)dx=2/xlnxdx

y=ln(x^2+e^x) 求Y'X

如果是求导数的话,y'=(2x+e^x)/(x^2+e^x)

y=ln(x-√x^2+a^2)-arcsin（a/x）y'=1/(x-√x^2+a^2)*(x-√x^2+a^2)'-1/√[1-(a/x)^2]*（a/x）'=1/(x-√x^2+a^2)*[1-

y=ln(x+√x^2+1),求y

x≤0时√x^2=-x所以y=0x>0时√x^2=x所以y=ln（2x+1）

y'=[[ln(2x)]'x^6-ln(2x)(x^6)']/[x^6]^2=[2/(2x)*x^6-6x^5ln(2x)]/x^12=(1-6ln(2x))/x^7y''=[(1-6ln(2x))'