∫(x^3 )*(sin x^2) dx 求不定积分

来源：学生作业帮编辑：灵鹊做题网作业帮分类：数学作业时间：2024/04/26 03:39:16

解
∫x³sinx²dx
=1/2∫x²sinx²dx²
=1/2∫usinudu
=-1/2∫ud(cosu)
=-1/2[ucosu-∫cosudu]
=-1/2ucosu+1/2sinu+C
=-1/2x²cosx²+1/2sinx²+C

求不定积分∫dx/sin^3 x ∫sin^3(x) dx 求不定积分求不定积分∫sin(x/2)dx 求不定积分：∫sin(x^2)dx ∫[(sin^2)x]dx求不定积分 ∫(x^3 )*(sin x^2) dx 求不定积分求不定积分 ∫sin(3x+2)dx? 求不定积分∫ sin(2x+3) dx 求不定积分∫1/sin^2(3x+4)dx 求不定积分x( sin^2)x dx 求不定积分：∫(sin x/cos^3 x)dx 求不定积分?∫ x sin(x/2) dx