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一道GRE关于四分位的题目求详解

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一道GRE关于四分位的题目求详解
The company a which Mark is employed has 80 employees,each of wom has a different salary.Mark's salary of $ 43,700 is the second-highest salary in the first quartile of the 80 salaries.If the conmpany were to hire 8 new employees at salaries that are less than the lowest of the 80 salaries,what would Mark's salary be with respect to the quartiles of the 88 salaries at the company,assuming no other changes in the salaries?
The fifth-lowest salary in the second quartile.
一道GRE关于四分位的题目求详解
公司80人,分四组(20人1组)
分别是 first(第61-80位),second(41-60),third(21-40),fourth(1-20)quartile
Mark 薪金原是在公司是1组第2位高,即first quartile 中的第62位
增加8人後,分四组(22人1组)
四组变化分别是 (67-88),(45-66),(23-44),(1-22)
因此第62位的Mark现在变成second quartile,(66 65 64 63 62..)的倒数第5位(fifth-lowest)
再问: 那为什么first quartile不是第1-20位呢? 为什么是从高到底排列?计算quartile 之前是不是应该将数字从低到高排列? 谢谢你哈!
再答: 四分位数(Quartile),即统计学中,把所有数值 "由小到大" 排列并分成四等份,处于三个分割点位置的得分就是四分位数。(百度百科) 因此根据Quartile定义,first quartile就是最小的25% 至於从高到底排列只是为了方便解题(第2高的话高到底排列快点..)及个人习惯>.