设y=f^2(3x-2/3x+2),f(x)=In(1+x^2),则dy/dx|x=0=?
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设y=f^2(3x-2/3x+2),f(x)=In(1+x^2),则dy/dx|x=0=?
f(x)=ln(x^2+1)
f((3 x-2)/(3 x+2))=ln^2((3 x - 2)^2/(3 x + 2)^2 + 1)
dy/dx=
(2 ((6 (3 x - 2))/(3 x + 2)^2 - (
6 (3 x - 2)^2)/(3 x + 2)^3) ln((3 x - 2)^2/(3 x + 2)^2 +
1))/((3 x - 2)^2/(3 x + 2)^2 + 1)
x=0时等于
-6ln2
f((3 x-2)/(3 x+2))=ln^2((3 x - 2)^2/(3 x + 2)^2 + 1)
dy/dx=
(2 ((6 (3 x - 2))/(3 x + 2)^2 - (
6 (3 x - 2)^2)/(3 x + 2)^3) ln((3 x - 2)^2/(3 x + 2)^2 +
1))/((3 x - 2)^2/(3 x + 2)^2 + 1)
x=0时等于
-6ln2
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