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(sin5π/12-sinπ/12)(cos5π/12+cosπ/12)=?

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(sin5π/12-sinπ/12)(cos5π/12+cosπ/12)=?
(sin5π/12-sinπ/12)(cos5π/12+cosπ/12)=?
(sin5π/12-sinπ/12)(cos5π/12+cosπ/12)
=(cosπ/12 - sinπ/12)(sinπ/12 + cosπ/12)
=cos²(π/12) - sin²(π/12)
=cos(π/6)
=(根号3)/2
再问: (sin5π/12-sinπ/12)(cos5π/12+cosπ/12)怎么会变成(cosπ/12 - sinπ/12)(sinπ/12 + cosπ/12)
再答: 公式:sin(π/2 - α)=cosα,cos(π/2 - α)=sinα