①X+Y+Z=111②Y:X=3:2③Y:Z=5:4
x+y+z=2 ① 2x+3y+z=38 ① x+y=3 3x-y-4z=5 ② 3x+4y+2z+56 ② y+z=5
解三元一次方程组:(一)2x+y+z=4① x-y+3z=3 ②x+z=2③ 二;①2x+y+z=2 ②x+2y+z=5
{5X+Y+Z①X+5Y+Z=-2②X+Y+5Z=10③
已知x/2=y/4=z/7,求①x:y:z.②若2x+y+3z=58,分别求x,y,z的值.③求x+y/x+z的值.
解三元一次方程组 2x=3y① 4y=5z② x+y+z=66③ 第二道 3x-y+z=4① 2x+3y-z=12② x
①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z-
x/2=y/3=z/5 x+3y-z/x-3y+z
三元一次方程求解:①x+2z=3,2x+y=2,2y+z=7.②x+y+z=2,3x-y-4z=5,2x+3y-2z=0
2x+4y-3z=9① 3x-2y-4z=8② 5x-6y-5z=7③
{5x+2y-4z=1① 3x-3y+2z=1② -2x+3y-2z=0③}
2x+4y+3z=9① 3x-2y+5z=11② 5x-6y+7z=13③
2x+3y+z=38 ① 3x+4y+2z=56 ② 4x+5y+z=66 ③