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解算式:2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)

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解算式:2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)
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解算式:2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)
2/(x+1)(x+3)+2/(x+3)(x+5)+.+2/(x+2001)(x+2003)
=[1/(x+1) -1/(x+3)]+[1/(x+3) -1/(x+5)]+.+[1/(x+2001) -1/(x+2003)]
= 1/(x+1) - 1/(x+2003)
= [(x+2003)-(x+1)]/[(x+1)(x+2003)]
= 2002/[(x+1)(x+2003)]