1.(x+1)(x+2)-x-10
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
(x/x-1)+(5x-2)/x*x-x=1 求x(有图)
1.若f(x+1/x)=x^2+1/x^2,求f(x)
(2x-2)(x-1)=0 x(x-5)=5x-10
(X-X*20%-18-(X-X*20%-18)*10%=X*1/2-3(过程)
1.(x²-x+2)(-x-2-x²)
(x-1)^3(x+1)(x-2)/(x+4)
(x+1)(x+2)(x+3)(x+4)+1
计算 x(x+3)-(x-1)(x-2)
化简{x²-2x分之x+2-x²-4x+4x分之x-1}除以X分之(x-1)(X-4)乘以(2-x)
(x+2/x+1)-(x+4/x+3)-(x+3/x+2)+(x+5/x+4)
[(x+2)/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x