数列叠乘问题a1=2/3 an+1=n/(n+1)an求an根据已知是an+1/an=n/n+1可是最后怎么这个条件用不

数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝. 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 已知数列{an}满足a1=1,an=(an-1)/3an-1+1,(n>=2,n属于N*),求数列{an}的通项公式 已知数列｛an｝中a1=6,且an-an-1=(an-1/n)+n+1(n属于N*,n≥2）,求an 已知数列{an}满足a1=1,a(n+1)=3an+2(n属于N) 1.求证数列{an+1}是等比数列 2.求{an}的 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 已知数列{an}满足a1=1/2,an+1=an+1/n的平方+n求an 已知数列an中,a1=2,an+1=an+lg(n/n+1)求an 已知数列{an}满足a1=33,an+1-an=2n 则求an/n? 已知数列{an}满足a1=33,an+1-an=2n 则求an/n的最小值 已知数列an满足:an+1-2an=2^n+1,且a1=2 (1)证明{an/2^n}是等差数列 (2)求数列an的 已知数列{an}满足 a1=3,an+1=an+3n²+3n+2-1\n(n+1),求an的通项公式