3(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)-2^64=

来源：学生作业帮编辑：灵鹊做题网作业帮分类：数学作业时间：2024/05/13 17:19:36

3(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)-2^64
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)-2^64
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)-2^64
=(2^8-1)(2^8+1)(2^16+1)(2^32+1)-2^64
=(2^16-1)(2^16+1)(2^32+1)-2^64
=(2^32-1)(2^32+1)-2^64
=2^64-1-2^64
=-1

(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1), 已知m=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128 设M=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1),试确定M-2 设M=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)（2^128+ 128+64+32+16+8+4+2+1+2/1+4/1+8/1+16/1+32/1=? 若A=(2+1)(2^2+1)(2^4+1)( 2^8+1)( 2^16+1)( 2^32+1)( 2^64+1) 求A (2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)=? 求和：1/2+1/4+1/8+1/16+1/32+1/64+.+1/1024=? 1-2/1-4/1-8/1-16/1-32/1-64/1=多少? 1-2/1-4/1-8/1-16/1-32/1-64/1=?简便计算 1/2+1/4+1/8+1/16+1/32+1/64+.+1024=? 1/2+1/4+1/8+1/16+1/32+1/64=?