化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x
来源:学生作业帮 编辑:灵鹊做题网作业帮 分类:数学作业 时间:2024/06/09 19:31:10
化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
=[sinx^2(1-sinx^2)+cosx^2(1-cosx^2)]/[sinx^2(1-sinx^4)+cosx^2(1-cosx^4)]
=2sinx^2cosx^2/[3*sinx^2cosx^2]
=2/3
√希望你能看懂,你能明白, 望采纳,赞同
=[sinx^2(1-sinx^2)+cosx^2(1-cosx^2)]/[sinx^2(1-sinx^4)+cosx^2(1-cosx^4)]
=2sinx^2cosx^2/[3*sinx^2cosx^2]
=2/3
√希望你能看懂,你能明白, 望采纳,赞同
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
化简 cos^2(x)*sin^2(x)-sin^2(x)
化简 cos^(2)(x)*sin^(2)(x)-sin^(2)(x)
已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x
证明sin^2(x)+cos^2(x+30)+sin(x)cos(x+30)=3/4
用cos x表示sin^4 x -sin^2 x +cos^2 x
cos 2x /sin^2 x*cos^2 x不定积分
2cos x (sin x -cos x)+1
(sin^2x+cos^2x )(sin^2x-cos^2x)怎么得sin^2x-cos^2x?
三角函数证明及化简题1.证明sin^6x+cos^6x=(sin^2x+cos^2x)(cos^4x-cos^2xsin
求证(cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2
∫sin(x) cos^2(x)dx