y=lim (cos2x)^(1+cot^2x)
lim(x→0)=(1/x^2-cot^2x)
求极限LIM(趋近与0)(cot^2 *x-1/x^2)
求解一道极限题lim【(cos2x)的1/sin2x次方】=?(x→0)
lim(x→0)(1-cos2x)/xsinx
求下列不定积分:1、(cot)^2•xdx 2、cos2x/(cos^2xsin^2x)dx
求极限 (1) x趋向x/6 lim ln(2cos2x) (2) x趋向0 lim(e^x-1)/x (3) x趋向0
lim x趋向0 1/x∧2— cot∧2x 求极限
x →0时lim(1+x^2)^cot^2x求极限要详细过程.
lim (arcsinx/x)^{[cot(x)]^2} x→0
已知4sin^2x-cos^2x+3cosx=0求(cos2x-cos^2x)/(1-cot^2x)
y=-1/2cot(π/3-2x)的周期为?单调区间为?
求极限:lim(x趋向0) [1-cosx(cos2x)^1/2(cos3x)^1/3]/[ln(1+x)-x]