第4第5题,难爆了!
来源:学生作业帮 编辑:灵鹊做题网作业帮 分类:化学作业 时间:2024/06/25 07:14:14
第4第5题,难爆了!
![](http://img.wesiedu.com/upload/1/49/149a700cc79b983d7542ed41c7fd8191.jpg)
![](http://img.wesiedu.com/upload/1/49/149a700cc79b983d7542ed41c7fd8191.jpg)
![第4第5题,难爆了!](/uploads/image/z/19799107-43-7.jpg?t=%E7%AC%AC4%E7%AC%AC5%E9%A2%98%2C%E9%9A%BE%E7%88%86%E4%BA%86%21%26nbsp%3B)
4,Y2X2
解析:
XY4=Y2+B
XY4:0.02/22.4mol
X:0.02/22.4mol,Y:0.08/22.4mol
A,0.03/22.4molY2中,Y元素物质的量=0.06/22.4mol
10mlB中X元素物质的量=0.02/22.4mol,Y元素物质的量=0.08/22.4mol-0.06mol/22.4mol=0.02/22.4mol
B分子中X原子个数=0.02/22.4mol/(0.01/22.4mol)=2
B分子中Y原子个数=0.02/22.4mol/(0.01/22.4mol)=2
除以B的物质的量求得B的化学式为Y2X2
氧气的系数等于XO2和YO2的系数之和,所以消耗氧气的体积等于生成XO2和YO2的体积之和
T(O2)=672ml=0.672L
参加反应氧气的物质的量n(O2)=0.672L/(22.4L/mol)=0.03mol
参加反应氧气的质量m(O2)=0.03molx32g/mol=0.96g
生成物的总质量=0.672Lx2.56g/L=1.72g
根据质量守恒,反应的XY2的质量m(XY2)=1.72032g-0.96g=0.76g
XY2与氧气的系数比为1:3,消耗氧气的物质的量为0.03mol,所以XY2的n(XY2)物质的量n(XY2)=0.01mol
XY2的摩尔质量M(XY2)=0.76g/0.01mol=76g/mol
答:
(1)反应前O2的体积为0.672L
(2)XY2的质量为0.76g
(3)XY2的摩尔质量为76g/mol
解析:
XY4=Y2+B
XY4:0.02/22.4mol
X:0.02/22.4mol,Y:0.08/22.4mol
A,0.03/22.4molY2中,Y元素物质的量=0.06/22.4mol
10mlB中X元素物质的量=0.02/22.4mol,Y元素物质的量=0.08/22.4mol-0.06mol/22.4mol=0.02/22.4mol
B分子中X原子个数=0.02/22.4mol/(0.01/22.4mol)=2
B分子中Y原子个数=0.02/22.4mol/(0.01/22.4mol)=2
除以B的物质的量求得B的化学式为Y2X2
氧气的系数等于XO2和YO2的系数之和,所以消耗氧气的体积等于生成XO2和YO2的体积之和
T(O2)=672ml=0.672L
参加反应氧气的物质的量n(O2)=0.672L/(22.4L/mol)=0.03mol
参加反应氧气的质量m(O2)=0.03molx32g/mol=0.96g
生成物的总质量=0.672Lx2.56g/L=1.72g
根据质量守恒,反应的XY2的质量m(XY2)=1.72032g-0.96g=0.76g
XY2与氧气的系数比为1:3,消耗氧气的物质的量为0.03mol,所以XY2的n(XY2)物质的量n(XY2)=0.01mol
XY2的摩尔质量M(XY2)=0.76g/0.01mol=76g/mol
答:
(1)反应前O2的体积为0.672L
(2)XY2的质量为0.76g
(3)XY2的摩尔质量为76g/mol