是关于化简的 70 4m²-4(3m²-3mn-2n²)+6-3n²1/3a-(
规定新运算:m#n=m+n,m﹡n=m-n,试化简[(mn²﹚#(2mn)]+[(4mn²)﹡(3m
已知-3/7a的(平方+m)b(2n-1)是四次单项式,求m²n-m²-m(4n+mn)-(-2n)
若(2m-n)²=3mn,求代数式n/m+4m/n-1的值
(7m²-4mn-n²)-(3m²-mn+2n²)求解
(4mn²+3m²n-4m)-2(mn²+3/2m²n+1)化简
已知m+n+=3,mn=三分之二,求m²+(n-m)²+2m(n-mn)的值
(m²-6mn+9n²)÷(m-3n)-(4m²-9n²)÷(2m-3n)化简,
(m²-6mn+9n²)÷(m-3n)-(4m²-9n²)-(2m-3n)怎么做
已知m+n=3,则2m²+4mn+2n²-6
已知m²+n²=5,mn=2,求代数式[6m²-5m(-m+3n)+4m(-4m+5/2n
(3m-2n)²+24mn
已知m-n=3,mn=-1,求多项式-2mn+2m+3n-3mn-2n+2m-4n-m-mn的值