(2m+n-p).(2m-n+p)怎么算
(2m+n–p)(2m–n+p)用平方差公式怎么算?
已知m,n,p都是整数,且|m-n|+|p-m|=1,则|p-m|+|m-n|+3(n-p)2=______.
若m=2n,p=2m,则m+n+p等于( )
若 P=2m,m=2n,则m+p-n等于()
(m+n+p-q)(m-n-p-q) 怎么算
运用乘法公式进行计算.(m-2n+p)(m+2n-p)
运用乘法公式计算计:(m-2n+3p)(m+2n+3p)
(m-2n+3p)(m+3n+3p)
已知m、n、p满足|2m|+m=0,|n|=n,p|p|=1.化简:|n|-|m-p-1|+|p+n|-|2n+1|.
一道初一代数化简题,已知m,n,p满足|2m|+n=0.|n|=n,p+|p|=1,化简|n|-|m-p-1|+|p+n
因式分解:m(m-n)(p-q)-n(n-m)(p-q).
计算:(m+2n-p)2.