在数列a1中,a1=1,当n>2或n=2时,其前n项和sn2=an(sn-1).求证:数列í1/Sný,是等差数列
数列{an}中,a1=1,n≥2时,其前n项的和Sn满足Sn2=an(Sn-12)
在数列an中,Sn是数列an前n项和,a1=1,当n≥2时,sn^2=an(Sn-1/2) (1)证明1/Sn为等差数列
设数列an的前n项和为Sn,a1=1,an=(Sn/n)+2(n-1)(n∈N*) 求证:数列an为等差数列,
1:在数列{an}中,a1=1,当n>=2时,其前n项和sn满足an+2sn*s(n-1)=0
数列an中,a1=1,当n大于等于2时,其前n项和满足sn^2=an(sn-1) 证明:数列{1/sn}是等差数列
已知数列{an}的前n项和为Sn,且满足Sn=Sn-1/2Sn-1 +1,a1=2,求证{1/Sn}是等差数列
已知数列{an}的前n项和为Sn,且满足an+2Sn*Sn-1=0,a1=1/2.求证:{1/Sn}是等差数列
已知数列an中,a1=1,当n≥2时,其前n项和Sn满足Sn^2=an(Sn-1/2)
已知数列{an}中,a1=1,当n≥2时,其前n项和Sn满足Sn²=an(Sn-1/2)
已知数列an中,a1=1,当n≥2时,其前n项和Sn平方=an(Sn-1/2) 求Sn表达式.
数列{an}中,a1=1,当n大于等于2时,其前n项的和Sn,满足Sn的平方=an(Sn-1)
已知数列an中,a1=1,当n≥2时,其前n项和为Sn,满足Sn²=an(Sn-1)