化简(x+2/2²-2x-x-1/2²-4x+4)÷2-4/x³-2x²
来源:学生作业帮 编辑:灵鹊做题网作业帮 分类:数学作业 时间:2024/06/16 23:32:58
化简(x+2/2²-2x-x-1/2²-4x+4)÷2-4/x³-2x²
〔(x+2/2²-2x)-(x-1/2²-4x+4)〕÷2-4/x³-2x²
〔(x+2/2²-2x)-(x-1/2²-4x+4)〕÷2-4/x³-2x²
题目应是〔(x+2/x²-2x)-(x-1/x²-4x+4)〕÷2-4/x³-2x²
=〔(x+2/x(x-2)-(x-1/(x-2)²)〕÷2-4/x³-2x²
=〔(x+2)(x-2)-x(x-1)]/x(x-2)² ÷2-4/x³-2x²
=〔x²-4-x²+x]/x(x-2)² ÷2-4/x³-2x²
=(x-4)/2x(x-2)² -4/x²(x-2)
=[x(x-4)-8(x-2)]/2x²(x-2)²
=[x²-4x-8x+16]/2x²(x-2)²
=[x²-12x+16]/2x²(x-2)²
=〔(x+2/x(x-2)-(x-1/(x-2)²)〕÷2-4/x³-2x²
=〔(x+2)(x-2)-x(x-1)]/x(x-2)² ÷2-4/x³-2x²
=〔x²-4-x²+x]/x(x-2)² ÷2-4/x³-2x²
=(x-4)/2x(x-2)² -4/x²(x-2)
=[x(x-4)-8(x-2)]/2x²(x-2)²
=[x²-4x-8x+16]/2x²(x-2)²
=[x²-12x+16]/2x²(x-2)²
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
(4x³)²×[x³-x(2x-1)]
化简{x²-2x分之x+2-x²-4x+4x分之x-1}除以X分之(x-1)(X-4)乘以(2-x)
[(x+2)/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x
计算:2x/(x-2)(x+1)÷(1-x/x+1)-x²+2x/x²-4?
3x⁷*x⁴+2x*x²*x⁴-4x⁵*(-x)²
2道分式计算[(x+4)(x-2)]/x³+2x²+x÷[(x-2)/x·(x+4)/(x+1)]2
先化解,在求值;(3x/x-1-x/x+1)÷x四次方-4x²/x³-x,其中x=根号2+2
(2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3)
化简,x²+4x /(2x-4)(x+4)-x+2/x² -4
解不等式-x³+4x²-x-4/2+x-x²≧x-2
(x+1)/(x²+3x+2)+(x²-2x)/(x²-4)