x+y-z=6,x+3y+2x=1,3x+2y-z=4
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
x/2=y/3=z/5 x+3y-z/x-3y+z
1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
解方程一;{x+y-z=6,x-3y+2z=1,3x+2y-z=-7.②{3x+4z=7,2x+3y+z=9,5x-9y
x+y+z=4 2x+3y-z=6 3x+2y+2z=10
2x-y+2z=-17 3x+y-3z=-4 x+y+z=6
x+y+z=2 4x+2y+z=4 2x+3y+z=1
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6}