(x²-x+1)÷(x²-x-1)=(x²+x)÷(x²+x-2)解方程
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(x²-x+1)÷(x²-x-1)=(x²+x)÷(x²+x-2)解方程
(x²-x+1)÷(x²-x-1)=(x²+x)÷(x²+x-2)
(x²-x+1)/(x²-x-1)=(x²+x)/(x²+x-2)
[(x²-x-1)+2]/(x²-x-1)=[(x²+x-2)+2]/(x²+x-2)
(x²-x-1)/(x²-x-1)+2/(x²-x-1)=(x²+x-2)/(x²+x-2)+2/(x²+x-2)
1+2/(x²-x-1)=1+2/(x²+x-2)
2/(x²-x-1)=2/(x²+x-2)
1/(x²-x-1)=1/(x²+x-2)
x²-x-1=x²+x-2
2x=1
x=1/2
经检验x=1/2是方程的解
(x²-x+1)/(x²-x-1)=(x²+x)/(x²+x-2)
[(x²-x-1)+2]/(x²-x-1)=[(x²+x-2)+2]/(x²+x-2)
(x²-x-1)/(x²-x-1)+2/(x²-x-1)=(x²+x-2)/(x²+x-2)+2/(x²+x-2)
1+2/(x²-x-1)=1+2/(x²+x-2)
2/(x²-x-1)=2/(x²+x-2)
1/(x²-x-1)=1/(x²+x-2)
x²-x-1=x²+x-2
2x=1
x=1/2
经检验x=1/2是方程的解
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