设f(x)=1/(1+e^(1/x)) 求 lim f(x) x->0
设函数f x=e^2x-2x,lim f'(x)/e^x -1等于 ,x→0
设函数f(x)有二阶连续导数,且(x->0)lim[f(x)-a]/[e^x^2-1]=0,(x->0)lim[f ‘’
设函数f(x)有二姐连续导数,且(x->0)lim[f(x)-a]/[e^x^2-1]=0,(x->0)lim[f ‘’
lim[f(x)]^g(x)=e^lim[f(x)-1]g(x).经验公式,
设f'(x) = 3^(1/2) ,求 lim(h→0) [f(x+mh) - f(x - nh)] / h ,(m ,
已知f(x)=ln(1+x) 求lim(x→0) f(x)/x
设函数f(x)连续,lim((f(x)/x)-1/x-(sinx/x^2))=2,f(0)=?
设f(x)在x=0的邻域内有三阶导数,且x->0时,lim(1+x+f(x)/x)^(1/x)=e^3.求(1):f(0
设F(x)在x=0处连续,已知当x趋近于0时,lim(1+f(x)/x)^1/sinx=e^2,求当x趋近于0时,lim
设f(x)有二阶导数,且f''(X)>0,lim(x趋于0)f(x)/x=1 ..证明:当x>0时,有f(x)>x
f(x)有定义,f(2x)=f(x)cos x,lim f(x)=f(0)=1(x趋于0时),求f(x)
设f(x)在x=0处连续,且lim (f(x)-1)/x=-1,x→0.,求f(0)