f(x)=sin(2x+π/4),若f(x)*f(-x)=1/4,x∈(π/4,π/2),求tanx的值
函数f(x)=(1+1/tanx)sin^2x-2sin(x+π/4)sin(x-π/4).若tana=2,求f(a).
若f(x)=sin(π/4)x,求f(1)+f(2)+.+f(2010)
已知函数f(x)=(1+1/tanx)sin(x)^2 -2sin(x+π/4)*cos(x+π/4)
已知函数f(x)=(1+1/tanx)sin^2-2sin(x+π/4)sin(x-π/4).求tana=2时,f(a)
已知函数f(x)=(1+1/tanx)sin2x-2sin(x+π/4)sin(x-π/4)
已知函数f(X)=(1+1/tanx)sin^2x+msin(x+π/4)sin(x-π/4) 当tana=2时,f(a
已知f(x)=cos^2x/1+sin^2x求f'(π/4)
已知函数f(x)=cos^4x-2sinxcosx-sin^4x (1)求f(x)的最小正周期 (2)若x ∈[0,π/
已知函数f(x)=(1-tanx)【1+ sin(2x+π/4 )】,求 f(x)定义域值域以及单调减区间
已知函数f(x)=4cos²x+sin²x-4cosx-2 (1)求f(π/3)的值.(2)求f(x
已知函数f(x)=sin(2x+π/2),设g(x)=f(x)+f(π/4-x),求函数g(x)的单调递增区间
f(x )=cos^4x-2sinxcosx-sin^4x (1)求周期T (2)若x∈【0,π/2】求f(x)值域